Ex 6.2, 11 - Prove f(x) = x2-x+1 is neither strictly increasing

Ex 6.2,11 - Chapter 6 Class 12 Application of Derivatives - Part 2
Ex 6.2,11 - Chapter 6 Class 12 Application of Derivatives - Part 3

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Ex 6.2, 11 Prove that the function f given by f (๐‘ฅ) = ๐‘ฅ^2 โ€“ ๐‘ฅ + 1 is neither strictly increasing nor strictly decreasing on (โ€“ 1, 1).Given f(๐‘ฅ) = ๐‘ฅ2 โ€“ ๐‘ฅ + 1 Finding fโ€™(๐’™) fโ€™(๐‘ฅ) = 2๐‘ฅ โ€“ 1 Putting fโ€™(๐’™) = 0 2๐‘ฅ โ€“ 1 = 0 2๐‘ฅ = 1 ๐‘ฅ = 1/2 Since ๐’™ โˆˆ (โˆ’๐Ÿ , ๐Ÿ) So, our number line looks like Hence, f(x) is strictly decreasing for ๐‘ฅ โˆˆ (โˆ’1 , 1/2) & f(x) is strictly increasing for ๐‘ฅ โˆˆ (1/2, 1) Hence, f(๐‘ฅ) is neither decreasing nor increasing on (โˆ’๐Ÿ , ๐Ÿ). Hence Proved

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