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Example 31 - Find local minimum value of f(x) = 3 + |x| - Examples

Example 31 - Chapter 6 Class 12 Application of Derivatives - Part 2


Transcript

Example 31 (Method 1) Find local minimum value of the function f given by f (π‘₯) = 3 + |π‘₯| , π‘₯ ∈ R. f (π‘₯) = 3 + |π‘₯| Since Value of |𝒙|β‰₯𝟎 So, Minimum value of |π‘₯|=0 Now, Minimum value of f (π‘₯) = 3 + Minimum value of |π‘₯| = 3 + 0 = 3 Hence minimum value of f (π‘₯) = 3 Example 31 (Method 2) Find local minimum value of the function f given by f (π‘₯) = 3 + |π‘₯|, π‘₯ ∈ R. f (π‘₯) = 3 + |π‘₯| From graph, f (π‘₯) is Minimum at π‘₯ = 0 So, Minimum value of f (π‘₯) = f (0) = 3

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.