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Example 31 - Find local minimum value of f(x) = 3 + |x| - Examples

Example 31 - Chapter 6 Class 12 Application of Derivatives - Part 2


Transcript

Example 31 (Method 1) Find local minimum value of the function f given by f (π‘₯) = 3 + |π‘₯| , π‘₯ ∈ R. f (π‘₯) = 3 + |π‘₯| Since Value of |𝒙|β‰₯𝟎 So, Minimum value of |π‘₯|=0 Now, Minimum value of f (π‘₯) = 3 + Minimum value of |π‘₯| = 3 + 0 = 3 Hence minimum value of f (π‘₯) = 3 Example 31 (Method 2) Find local minimum value of the function f given by f (π‘₯) = 3 + |π‘₯|, π‘₯ ∈ R. f (π‘₯) = 3 + |π‘₯| From graph, f (π‘₯) is Minimum at π‘₯ = 0 So, Minimum value of f (π‘₯) = f (0) = 3

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.