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Last updated at April 19, 2021 by Teachoo

Example 31 (Method 1) Find local minimum value of the function f given by f (π₯) = 3 + |π₯| , π₯ β R. f (π₯) = 3 + |π₯| Since Value of |π|β₯π So, Minimum value of |π₯|=0 Now, Minimum value of f (π₯) = 3 + Minimum value of |π₯| = 3 + 0 = 3 Hence minimum value of f (π₯) = 3 Example 31 (Method 2) Find local minimum value of the function f given by f (π₯) = 3 + |π₯|, π₯ β R. f (π₯) = 3 + |π₯| From graph, f (π₯) is Minimum at π₯ = 0 So, Minimum value of f (π₯) = f (0) = 3