Check Full Chapter Explained - Continuity and Differentiability - Application of Derivatives (AOD) Class 12

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  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

Transcript

If x = 2 y = (โˆ’2)/(๐‘ฅ โˆ’ 3) y = (โˆ’2)/(2 โˆ’ 3) ๐‘ฆ=2 Thus, point is (2, 2) If x = 4 y = (โˆ’2)/(๐‘ฅ โˆ’ 3) y = (โˆ’2)/(4 โˆ’ 3) ๐‘ฆ=โˆ’2 Thus, point is (4, โ€“2) Thus, there are 2 tangents to the curve with slope 2 and passing through points (2, 2) and (4, โˆ’ 2) We know that Equation of line at (๐‘ฅ1 , ๐‘ฆ1)& having Slope m is ๐‘ฆโˆ’๐‘ฆ1=๐‘š(๐‘ฅโˆ’๐‘ฅ1) Equation of tangent through (2, 2) is ๐‘ฆ โˆ’ 2 = 2 (๐‘ฅ โˆ’2) ๐‘ฆ โˆ’ 2 = 2๐‘ฅ โˆ’ 4 ๐’šโˆ’๐Ÿ๐’™+๐Ÿ = ๐ŸŽ Equation of tangent through (4, โˆ’2) is ๐‘ฆ โˆ’(โˆ’2) = 2 (๐‘ฅ โˆ’4) ๐‘ฆ + 2 = 2๐‘ฅ โˆ’ 8 ๐’š โˆ’ ๐Ÿ๐’™ + ๐Ÿ๐ŸŽ = ๐ŸŽ

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.