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Ex 6.5,2 - Chapter 6 Class 12 Application of Derivatives - Part 2

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Ex 6.5, 2 Find the maximum and minimum values, if any, of the following functions given by (ii) 𝑓(π‘₯)= – | π‘₯ +1|+3f(π‘₯)= – | π‘₯ +1|+3 We know that | π‘₯ +1|β‰₯0 So, βˆ’| π‘₯ +1|≀0 Maximum value of g(π‘₯) = maximum value of – | π‘₯ +1|+3 = 0 + 3 = 3 Hence maximum value of f(x) is 3 And there is no minimum value of f(x)

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