# Ex 6.5,11 - Chapter 6 Class 12 Application of Derivatives

Last updated at March 11, 2017 by Teachoo

Last updated at March 11, 2017 by Teachoo

Transcript

Ex 6.5,11 It is given that at đ„ = 1, the function đ„4 â 62đ„2 + đđ„+ 9 attains its maximum value, on the interval [0, 2]. Find the value of a. We have fï·đ„ï·Ż=đ„4 â 62đ„2 + đđ„+ 9 Finding fâï·đ„ï·Ż fâï·đ„ï·Ż=ï·đï·ï·đ„ï·ź4ï·Żâ 62ï·đ„ï·ź2ï·Ż + đđ„ + 9ï·Żï·źđđ„ï·Ż = ï·4đ„ï·ź3ï·Żâ62 Ă2đ„+đ = ï·4đ„ï·ź3ï·Żâ124đ„+đ Given that at đ„=1, fï·đ„ï·Ż=ï·đ„ï·ź4ï·Żâ62ï·đ„ï·ź2ï·Ż+đđ„+9 attain its Maximum Value i.e. fï·đ„ï·Ż maximum at đ„=1 âŽ đâï·đ„ï·Ż=0 at đ„=1 Now, fâï·1ï·Ż=0 4ï·ï·1ï·Żï·ź3ï·Żâ124ï·1ï·Ż+đ=0 4 â 124 + a = 0 â 120 + a = 0 a = 120 Hence a = 120

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Chapter 6 Class 12 Application of Derivatives

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.