Ex 7.2, 24 - Chapter 7 Class 12 Integrals
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 7.2, 24 2 cos𝑥 − 3 sin𝑥6 cos𝑥 + 4 sin𝑥 Step 1: Let 6 cos𝑥 + 4 sin𝑥=𝑡 Differentiating both sides 𝑤.𝑟.𝑡.𝑥 −6 sin𝑥 + 4 co𝑠𝑥= 𝑑𝑡𝑑𝑥 4 cos𝑥−6 sin𝑥𝑑𝑥 =𝑑𝑡 𝑑𝑥 = 𝑑𝑡4 cos𝑥 − 6 sin𝑥 Step 2: Integrating the function 2 cos𝑥 − 3 sin𝑥6 cos𝑥 + 4 sin𝑥 . 𝑑𝑥 Putting 6 𝑐𝑜𝑠𝑥+4 𝑠𝑖𝑛𝑥=𝑡 & 𝑑𝑥= 𝑑𝑡4 cos𝑥 − 6 sin𝑥 = 2 cos𝑥 − 3 sin𝑥𝑡 . 𝑑𝑥 = 2 cos𝑥 − 3 sin𝑥𝑡 . 𝑑𝑡4 cos𝑥 − 6 sin𝑥 = 2 cos𝑥 − 3 sin𝑥𝑡 . 𝑑𝑡2 2 cos𝑥 − 3 sin𝑥 = 12𝑡. 𝑑𝑡 = 12 𝑑𝑡𝑡 = 12 log 𝑡+𝐶1 = 12 log 4 sin𝑥+6 cos𝑥+𝐶1 = 12 log 2 2 sin𝑥+3 cos𝑥+𝐶1 = 12 log 2+𝑙𝑜𝑔 2 sin𝑥+3 cos𝑥+𝐶1 = 12 log 2+ 12 𝑙𝑜𝑔 2 sin𝑥+3 cos𝑥+𝐶1 = 𝟏𝟐 𝒍𝒐𝒈 𝟐 𝒔𝒊𝒏𝒙+𝟑 𝒄𝒐𝒔𝒙+𝑪
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo