Ex 6.3, 5 (i) - For f(x) = x^3, x ∈ [-2, 2], find absolute maximum and - Ex 6.3

part 2 - Ex 6.3, 5 (i) - Ex 6.3 - Serial order wise - Chapter 6 Class 12 Application of Derivatives

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Ex 6.3, 5 Find the absolute maximum value and the absolute minimum value of the following functions in the given intervals: (i) f (š‘„) = š‘„3, š‘„āˆˆ[– 2, 2]Finding f’(š’™) f’(š‘„)=š‘‘(š‘„^3 )/š‘‘š‘„ f’(š‘„)=3š‘„^2 Putting f’(š’™)=šŸŽ 3š‘„^2=0 š‘„^2=0 š‘„=0 So, š‘„=0 is critical point Since given interval is š‘„ ∈ [āˆ’2 , 2] Hence calculating f(š‘„) at š‘„=āˆ’2 , 0 , 2 Absolute Maximum value of f(x) is 8 at š’™ = 2 & Absolute Minimum value of f(x) is –8 at š’™ = –2

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