Ex 7.3, 23
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 7.3, 23 𝑠𝑖𝑛2 𝑥−𝑐𝑜𝑠2 𝑥𝑠𝑖𝑛2 𝑥 𝑐𝑜𝑠2 𝑥 𝑑𝑥 is equal to (A)tan x + cot x + C (B) tan x + cosec x + C (C) − tan x + cot x + C (D) tan x + sec x + C sin2𝑥 − cos2𝑥 sin2𝑥 cos2𝑥𝑑𝑥 = sin2𝑥 sin2𝑥 cos2𝑥 − cos2𝑥 sin2𝑥 cos2𝑥𝑑𝑥 = 1 cos2𝑥 − 1 sin2𝑥𝑑𝑥 = sec2𝑥𝑑𝑥− 𝑐𝑜𝑠𝑒 𝑐2𝑥𝑑𝑥 = tan𝑥− − cot𝑥+𝐶 = tan𝑥+ cot𝑥+𝐶 Hence correct answer is (A).
Ex 7.3
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Ex 7.3, 23 You are here
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