Ex 7.3, 16
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 7.3, 16 tan4 𝑥𝑑𝑥 tan4 𝑥𝑑𝑥= tan2 𝑥 . tan2𝑥𝑑𝑥 = sec2𝑥−1 tan2𝑥𝑑𝑥 = sec2𝑥. tan2𝑥− tan2𝑥𝑑𝑥 = tan2𝑥. sec2𝑥𝑑𝑥− tan2𝑥𝑑𝑥 Now, tan4 𝑥𝑑𝑥= tan2 𝑥 . sec2𝑥𝑑𝑥− tan2 𝑥 𝑑𝑥 = tan3𝑥3+𝐶1− tan𝑥−𝑥+𝐶2 = tan3𝑥3 − tan𝑥+𝑥+𝐶1−𝐶2 = 𝒕𝒂𝒏𝟑𝒙𝟑 − 𝒕𝒂𝒏𝒙+𝒙+𝑪
Ex 7.3
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Ex 7.3, 16 You are here
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.