Ex 7.3, 12 - Class 12
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 7.3, 12 (๐ ๐๐2 ๐ฅ)/(1 + cosโก๐ฅ ) โซ1โ(๐ ๐๐2 ๐ฅ)/(1 + cosโก๐ฅ ) ๐๐ฅ=โซ1โ(1 โ cos^2โก๐ฅ)/(1 + cosโก๐ฅ ) ๐๐ฅ =โซ1โ((1)^2 โ cos^2โก๐ฅ)/(1 + cosโก๐ฅ ) ๐๐ฅ =โซ1โ(1 โ cosโก๐ฅ )(1 + cosโก๐ฅ )/(1 + cosโก๐ฅ ) ๐๐ฅ =โซ1โ(1โcosโก๐ฅ ) ๐๐ฅ =โซ1โ1 ๐๐ฅโโซ1โcosโก๐ฅ ๐๐ฅ =๐โ๐๐๐โก๐+๐ช
Ex 7.3
Ex 7.3, 1
Ex 7.3, 2
Ex 7.3, 3
Ex 7.3, 4
Ex 7.3, 5
Ex 7.3, 6 Important
Ex 7.3, 7
Ex 7.3, 8
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Ex 7.3, 11
Ex 7.3, 12 You are here
Ex 7.3, 13 Important
Ex 7.3, 14
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Ex 7.3, 16
Ex 7.3, 17
Ex 7.3, 18 Important
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Ex 7.3, 22 Important
Ex 7.3, 23
Ex 7.3, 24 Important
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.