Ex 7.3, 18 - Class 12
Last updated at March 11, 2017 by Teachoo
Transcript
Ex 7.3, 18 (cosโก2๐ฅ + 2 sin^2โก๐ฅ)/cos^2โก๐ฅ ๐๐ฅ โซ1โ(cosโก2๐ฅ + 2 sin^2โก๐ฅ)/cos^2โก๐ฅ ๐๐ฅ =โซ1โ(1 โ 2 sin^2โก๐ฅ + 2 sin^2โก๐ฅ)/cos^2โก๐ฅ ๐๐ฅ =โซ1โ1/cos^2โก๐ฅ ๐๐ฅ =โซ1โsec^2โก๐ฅ ๐๐ฅ =๐ญ๐๐งโก๐+๐ช
Ex 7.3
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Ex 7.3, 18 Important You are here
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.