Ex 7.11, 20 - Chapter 7 Class 12 Integrals

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Ex 7.11, 20 Choose the correct answer : The value of 2 2 3 + + tan 5 +1 (A) 0 (B) 2 (C) (D) 1 2 2 3 + + tan 5 +1 + = 0, = &2 0 , = Hence = 2 2 3 + + tan 5 +1 = 0 2 0 + 0 2 0 + 0 2 0 +2 0 2 = 2 0 2 = 2 0 2 = 2 2 = Now taking I2 i.e. I2 = 2 2 1. I2 = 2 2 I2 = 2 2 I2 = 2 + 2 I2 = + 2 I2 = 2 2 I2 = Put the value of I1 and I2 in equation (1), we get 2 2 3 + + tan +1 = 2 2 3 + + tan + 2 2 1. = 0 + = Option C