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Transcript

Ex 7.10, 9 By using the properties of definite integrals, evaluate the integrals : โˆซ_0^2โ–’๐‘ฅโกโˆš(2โˆ’๐‘ฅ) ๐‘‘๐‘ฅ Let I=โˆซ_0^2โ–’ใ€–๐‘ฅโˆš(2โˆ’๐‘ฅ) ๐‘‘๐‘ฅใ€— โˆด I=โˆซ_0^2โ–’ใ€–(2โˆ’๐‘ฅ) โˆš(2โˆ’(2โˆ’๐‘ฅ) ) ๐‘‘๐‘ฅใ€— I=โˆซ_0^2โ–’ใ€–(2โˆ’๐‘ฅ) โˆš(2โˆ’2+๐‘ฅ ) ๐‘‘๐‘ฅใ€— I=โˆซ_0^2โ–’ใ€–(2โˆ’๐‘ฅ) โˆš(๐‘ฅ ) ๐‘‘๐‘ฅใ€— I=โˆซ_0^2โ–’ใ€–(2โˆ’๐‘ฅ) (๐‘ฅ)^(1/2) ๐‘‘๐‘ฅใ€— I=โˆซ_0^2โ–’ใ€–(2. ๐‘ฅ^(1/2)โˆ’๐‘ฅ.ใ€– ๐‘ฅใ€—^(1/2) ) ๐‘‘๐‘ฅใ€— I=2โˆซ_0^2โ–’ใ€–๐‘ฅ^(1/2) ๐‘‘๐‘ฅใ€— โˆ’โˆซ_0^2โ–’ใ€–๐‘ฅ. ๐‘ฅ^(3/2) ๐‘‘๐‘ฅใ€— I=2[๐‘ฅ^(1/2 + 1)/(1/2 + 1)]_0^2โˆ’ [๐‘ฅ^(3/2 + 1)/(3/2 + 1)]_0^2 I=2[๐‘ฅ^(3/2 )/(3/2)]_0^2โˆ’ [๐‘ฅ^(5/2)/(5/2)]_0^2 I=(2. 2)/3 [๐‘ฅ^(3/2) ]_0^2โˆ’ ใ€–2/5 [๐‘ฅ^(5/2) ]ใ€—_0^2 I=4/3 [(2)^(3/2)โˆ’(0)^(3/2) ] โˆ’ 2/5 [(2)^(5/2)โˆ’(0)^(5/2) ] I=4/3 [(2)^(3/2) ] โˆ’ 2/5 [(2)^(5/2) ] I=4/3 [[(2)^(1/2) ]^3 ] โˆ’ 2/5 [[(2)^(1/2) ]^3 ] I=4/3 [(โˆš2)^3 ] โˆ’ 2/5 [(โˆš2)^5 ] I=4/3 [2โˆš2] โˆ’ 2/5 [4โˆš2] I=(8โˆš2)/3โˆ’(8โˆš2)/5 I=8โˆš2 [1/3โˆ’1/5] I=8โˆš2 [2/15] ๐ˆ=(๐Ÿ๐Ÿ”โˆš๐Ÿ)/๐Ÿ๐Ÿ“

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.