
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 7.11, 6 By using the properties of definite integrals, evaluate the integrals: 28 𝑥−5𝑑𝑥 𝑥−5= 𝑥−5, 𝑖𝑓 𝑥−5≥0− 𝑥−5 𝑖𝑓 𝑥−5<0 = 𝑥−5 𝑖𝑓 𝑥≥5− 𝑥−5 𝑖𝑓 𝑥<5 ∴ 28 𝑥−5𝑑𝑥= 25− 𝑥−5𝑑𝑥+ 58 𝑥−5𝑑𝑥 =− 𝑥22−5𝑥25+ 𝑥22−5𝑥58 =− 522−5×5+ 222−5×2+ 822−5×8− 522−5×5 =− 252+25+2−10+32−40− 252+25 =− 252−25+25−10−40+32+2 = −502+50−50+34 = −502+34 = 182 = 9
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