Ex 7.11, 14
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 7.11, 14 By using the properties of definite integrals, evaluate the integrals : 02𝜋 cos5𝑥 𝑑𝑥 02𝜋 cos5𝑥 𝑑𝑥 = 0𝜋 cos5𝑥 𝑑𝑥+ 0𝜋(2π−𝑥) 𝑑𝑥 = 0𝜋 𝑐𝑜𝑠5𝑥 𝑑𝑥+ 0𝜋 𝑐𝑜𝑠5 𝑥 = 2 0𝜋 𝑐𝑜𝑠5𝑥 𝑑𝑥 = 2 0 𝜋2 𝑐𝑜𝑠5𝑥 𝑑𝑥+ 0 𝜋2 cos 𝜋−𝑥 𝑑𝑥 = 2 0 𝜋2 𝑐𝑜𝑠5𝑥 𝑑𝑥+ 0 𝜋2 − cos𝑥5𝑑𝑥 = 2 0 𝜋2 𝑐𝑜𝑠5𝑥𝑑𝑥−2 0 𝜋2 𝑐𝑜𝑠5𝑥 = 0
About the Author
CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .