Example 5 (iii) - Chapter 7 Class 12 Integrals

Last updated at August 18, 2026 by

Example 5 - Chapter 7 Class 12 Integrals - Part 4

Example 5 - Chapter 7 Class 12 Integrals - Part 5

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Example 5 Integrate the following functions . . . : (iii) tan 4 sec 2 tan 4 sec 2 Let t = tan = 2 1 2 2dt = dx 2 Substituting value, 4 2 = 4 2 = 2 4 = 2 5 5 + C Putting back value of t = 2 5 5 + C

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