Example 25 (iii) - Evaluate Integral ∫ x dx / (x + 1) (x + 2) from 1 - Examples

part 2 - Example 25 (iii) - Examples - Serial order wise - Chapter 7 Class 12 Integrals
part 3 - Example 25 (iii) - Examples - Serial order wise - Chapter 7 Class 12 Integrals
part 4 - Example 25 (iii) - Examples - Serial order wise - Chapter 7 Class 12 Integrals

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Example 25 Evaluate the following integrals: (iii) ∫_1^2ā–’(š‘„ š‘‘š‘„)/((š‘„ + 1) (š‘„ + 2) ) š‘‘š‘„ š¹(š‘„)=∫1ā–’(š‘„ š‘‘š‘„)/(š‘„ + 1)(š‘„ + 2) We can write the integrate as : š‘„/(š‘„ + 1)(š‘„ + 2) =A/(š‘„ + 1)+B/(š‘„ + 2) š‘„/(š‘„ + 1)(š‘„ + 2) =(A(š‘„ + 2) + B(š‘„ + 1))/(š‘„ + 1)(š‘„ + 2) Canceling denominators š‘„=A(š‘„+2)+B(š‘„+1) Putting š’™=āˆ’šŸ āˆ’2=A(2+2)+B(2+1) āˆ’2=A Ɨ0+B(āˆ’1) āˆ’2=āˆ’B B=2 Putting š’™=āˆ’šŸ āˆ’1=A(āˆ’1+2)+B(āˆ’1+1) āˆ’1=A(1)+B(0) āˆ’1=A A=āˆ’1 =āˆ’š‘™š‘œš‘”|š‘„+1|+š‘™š‘œš‘”|š‘„+2|^2 =š‘™š‘œš‘”|š‘„+2|^2āˆ’š‘™š‘œš‘”|š‘„+1| =š‘™š‘œš‘”|(š‘„ + 2)^2/(š‘„ + 1)| Hence š¹(š‘„)=š‘™š‘œš‘”|(š‘„ + 2)^2/(š‘„ + 1)| Now, ∫_1^2ā–’ć€–š‘„/(š‘„ + 1)(š‘„ + 2) š‘‘š‘„ć€—=š¹(2)āˆ’š¹(1) ∫_1^2ā–’ć€–š‘„/(š‘„ + 1)(š‘„ + 2) š‘‘š‘„ć€—=š‘™š‘œš‘”|(2 + 2)^2/(2 + 1)|āˆ’š‘™š‘œš‘”|(1 + 2)^2/(1 + 1)| =š‘™š‘œš‘”|(4)^2/3|āˆ’š‘™š‘œš‘”|(3)^2/2| =š‘™š‘œš‘”|(4^2/3)/(3^2/2)| =š‘™š‘œš‘”|4^2/3 Ɨ 2/3^2 | =š‘™š‘œš‘”|16/3 Ɨ 2/9| =š‘™š‘œš‘”|32/27 | =š„šØš ā”(šŸ‘šŸ/šŸšŸ•)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo