Check sibling questions

Example 37 - Evaluate integral cos 6x root 1 + sin 6x dx - Integration by substitution - Trignometric - Normal

Example 37 - Chapter 7 Class 12 Integrals - Part 2
Example 37 - Chapter 7 Class 12 Integrals - Part 3


Transcript

Example 37 Evaluate cos 6 1+ sin 6 cos 6 1+ sin 6 Put = 1+ sin 6 2 = 1+ sin 6 Differentiate . . . 2 = 1+ sin 6 2 . =6 cos 6 2 6 cos 6 = Therefore, cos 6 1+ sin 6 = cos 6 . 2 6 cos 6 = 2 3 = 1 3 2 = 1 3 2 + 1 2 + 1 + = 1 3 3 3 + = 3 9 + Putting back = 1+ 6 = 1 + sin 6 3 9 + = 1 + sin 6 1 2 3 9 + = + +

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.