Examples

Chapter 5 Class 12 Continuity and Differentiability
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Example 38 Find π2π¦/ππ₯2 , if π¦ = π₯3+tanβ‘π₯. π¦ = π₯3+tanβ‘π₯ Differentiating π€.π.π‘.π₯ ππ¦/ππ₯ = (π(π₯^3+ tanβ‘γπ₯)γ)/ππ₯ ππ¦/ππ₯ = (π(π₯^3))/ππ₯ + (π(tanβ‘γπ₯)γ)/ππ₯ ππ/ππ = πππ+ππππ π Again Differentiating π€.π.π‘.π₯ (π^2 π¦)/γππ₯γ^2 = (π (3π₯2 +sec^2β‘π₯))/ππ₯ (π^2 π¦)/γππ₯γ^2 = (π (3π₯2))/ππ₯ + (π (sec2 π₯))/ππ₯ (π^2 π¦)/γππ₯γ^2 = 6π₯+2 secβ‘π₯ . (π(secβ‘γπ₯)γ)/ππ₯ (π^2 π¦)/γππ₯γ^2 = 6π₯+2 secβ‘π₯.secβ‘γπ₯ tanβ‘π₯ γ γππγ^π/γππγ^π = ππ+π γπππγ^πβ‘π . π­ππ§β‘π

#### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.