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Example 29 - Chapter 5 Class 12 Continuity and Differentiability - Part 4

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Example 29 Differentiate the following w.r.t. x: (iv) π‘’π‘π‘œπ‘  π‘₯Let 𝑦 = 𝑒^cos⁑π‘₯ Differentiating both sides 𝑀.π‘Ÿ.𝑑.π‘₯ 𝑑𝑦/𝑑π‘₯ = 𝑑(𝑒^cos⁑π‘₯ )/𝑑π‘₯ 𝑑𝑦/𝑑π‘₯ = 𝑒^cos⁑π‘₯ . 𝑑(cos⁑π‘₯ )/𝑑π‘₯ 𝑑𝑦/𝑑π‘₯ = 𝑒^cos⁑π‘₯ . (βˆ’sin⁑π‘₯ ) π’…π’š/𝒅𝒙 = γ€–βˆ’π’”π’Šπ’β‘π’™. 𝒆〗^𝒄𝒐𝒔⁑𝒙 ((𝑒^π‘₯)β€²=𝑒^π‘₯) ((cos⁑〖π‘₯)β€²=βˆ’sin⁑π‘₯ γ€— )

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.