Misc 1 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at Dec. 24, 2018 by Teachoo

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Misc 1 - Differentiate (3x2 - 9x + 5)9 - Chapter 5 Class 12 - Finding derivative of a function by chain rule

Transcript

Misc 1 Differentiate w.r.t. x the function, (3𝑥2 – 9𝑥 + 5)^9 Let 𝑦=(3𝑥2 – 9𝑥 + 5)^9 Differentiating 𝑤.𝑟.𝑡.𝑥. 𝑑𝑦/𝑑𝑥 = (𝑑(3𝑥2 – 9𝑥 + 5)^9)/𝑑𝑥 = 9(3𝑥2 – 9𝑥 + 5)^(9 −1) . 𝑑(3𝑥2 – 9𝑥 + 5)/𝑑𝑥 = 9(3𝑥2 – 9𝑥 + 5)^8 . (𝑑(3𝑥2)/𝑑𝑥 − 𝑑(9𝑥)/𝑑𝑥 − 𝑑(5)/𝑑𝑥) = 9(3𝑥2 – 9𝑥 + 5)^8 . (6𝑥−9+0) = 9(3𝑥2 – 9𝑥 + 5)^8 . (6𝑥−9) = 9(3𝑥2 – 9𝑥 + 5)^8 . 3(2𝑥−3) = 27(3𝑥2 – 9𝑥 + 5)^8 (2𝑥−3) Hence, 𝒅𝒚/𝒅𝒙 = 𝟐𝟕(𝟑𝒙𝟐 – 𝟗𝒙 + 𝟓)^𝟖 (𝟐𝒙−𝟑)

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Chapter 5 Class 12 Continuity and Differentiability

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.