Misc 1 - Class 12
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Misc 1 Differentiate w.r.t. x the function, 3𝑥2 – 9𝑥 + 59 Let 𝑦= 3𝑥2 – 9𝑥 + 59 Differentiating 𝑤.𝑟.𝑡.𝑥. 𝑑𝑦𝑑𝑥 = 𝑑 3𝑥2 – 9𝑥 + 59𝑑𝑥 = 9 3𝑥2 – 9𝑥 + 59 −1 . 𝑑 3𝑥2 – 9𝑥 + 5𝑑𝑥 = 9 3𝑥2 – 9𝑥 + 58 . 𝑑 3𝑥2𝑑𝑥 − 𝑑 9𝑥𝑑𝑥 − 𝑑 5𝑑𝑥 = 9 3𝑥2 – 9𝑥 + 58 . 6𝑥−9+0 = 9 3𝑥2 – 9𝑥 + 58 . 6𝑥−9 = 9 3𝑥2 – 9𝑥 + 58 . 3 2𝑥−3 = 27 3𝑥2 – 9𝑥 + 5 2𝑥−3 Hence, 𝒅𝒚𝒅𝒙 = 𝟐𝟕 𝟑𝒙𝟐 – 𝟗𝒙 + 𝟓 𝟐𝒙−𝟑
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.