# Misc 11 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at Sept. 17, 2019 by Teachoo

Last updated at Sept. 17, 2019 by Teachoo

Transcript

Misc 11 (Method 1) Differentiate w.r.t. x the function, 2 3 +( 3) 2 , for > 3 Calculating = 2 3 Taking log on both sides log = log 2 3 log = ( 2 3). log Differentiating . . . . log = ( 2 3) log log . = ( 2 3) log = 2 3 2 . log + 2 3 Calculating = ( 3) 2 Taking log on both sides log = log ( 3) 2 log = 2 . log ( 3) Differentiating . . . . log = 2 . log ( 3) log . = 2 . log ( 3) log . = 2 . log ( 3) 1 . = 2 . log ( 3) 1 . = 2 . log ( 3) + log ( 3) . 2 1 . = 2 . log ( 3) + 1 3 . ( 3) . 2 1 . = 2 . log ( 3) + 1 3 . 2 1 . = 2 . log ( 3) + 2 3 = 2 . log ( 3) + 2 3 = ( 3) 2 2 . log ( 3) + 2 3 Now, = + = 2 3 2 . log + 2 3 + ( 3) 2 2 . log ( 3) + 2 3 = + + ( ) + .

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.