1. Chapter 5 Class 12 Continuity and Differentiability
  2. Serial order wise
  3. Ex 5.7

Ex 5.7, 1 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at May 29, 2018 by

Ex 5.7, 1 - Find second order derivatives of x2 + 3x + 2 - Ex 5.7

Slide2.JPG

  1. Chapter 5 Class 12 Continuity and Differentiability
  2. Serial order wise
    3. Ex 5.7
    Ex 5.8 →
Ask Download

Transcript

Ex 5.7, 1 Find the second order derivatives of the function ๐‘ฅ^2 + 3๐‘ฅ + 2 Let ๐‘ฆ = ๐‘ฅ^2 + 3๐‘ฅ + 2 Differentiating ๐‘ค.๐‘Ÿ.๐‘ก.๐‘ฅ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘(๐‘ฅ^2 + 3๐‘ฅ + 2))/(๐‘‘๐‘ฅ ) ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘(๐‘ฅ^2))/๐‘‘๐‘ฅ + (๐‘‘(3๐‘ฅ) )/๐‘‘๐‘ฅ + (๐‘‘(2) )/๐‘‘๐‘ฅ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = 2๐‘ฅ+3+0 ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = 2๐‘ฅ + 3 Again Differentiating ๐‘ค.๐‘Ÿ.๐‘ก.๐‘ฅ ๐‘‘/๐‘‘๐‘ฅ (๐‘‘๐‘ฆ/๐‘‘๐‘ฅ) = (๐‘‘ (2๐‘ฅ + 3))/๐‘‘๐‘ฅ (๐‘‘^2 ๐‘ฆ)/ใ€–๐‘‘๐‘ฅใ€—^2 = ๐‘‘(2๐‘ฅ)/๐‘‘๐‘ฅ + ๐‘‘(3)/๐‘‘๐‘ฅ = 2 + 0 = 2 Thus, (๐’…^๐Ÿ ๐’š)/(๐’…๐’™^๐Ÿ ) = 2

Chapter 5 Class 12 Continuity and Differentiability
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.