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Ex 5.6, 1 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at May 29, 2023 by

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Ex 5.6, 1 If x and y are connected parametrically by the equations without eliminating the parameter, Find ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ, x = 2ใ€–๐‘Ž๐‘กใ€—^2, y = ใ€–๐‘Ž๐‘กใ€—^4Here ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘๐‘ฆ/๐‘‘๐‘ก)/(๐‘‘๐‘ฅ/๐‘‘๐‘ก) Calculating ๐’…๐’š/๐’…๐’• ๐‘ฆ = ใ€–๐‘Ž๐‘กใ€—^4 ๐‘‘๐‘ฆ/๐‘‘๐‘ก " =" ใ€–4๐‘Ž๐‘กใ€—^(4 โˆ’1) "=" ใ€–4๐‘Ž๐‘กใ€—^3 Calculating ๐’…๐’™/๐’…๐’• ๐‘ฅ = 2ใ€–๐‘Ž๐‘กใ€—^2 ๐‘‘๐‘ฅ/๐‘‘๐‘ก " =" 2 ร— 2๐‘Ž๐‘ก "=" 4๐‘Ž๐‘ก Now, ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘๐‘ฆ/๐‘‘๐‘ก)/(๐‘‘๐‘ฅ/๐‘‘๐‘ก) Putting values ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (4๐‘Ž๐‘ก^3)/4๐‘Ž๐‘ก ๐’…๐’š/๐’…๐’™ = t2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.