Ex 5.6, 1 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at Dec. 16, 2024 by

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Ex 5.6, 1 If x and y are connected parametrically by the equations without eliminating the parameter, Find ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ, x = 2ใ€–๐‘Ž๐‘กใ€—^2, y = ใ€–๐‘Ž๐‘กใ€—^4Here ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘๐‘ฆ/๐‘‘๐‘ก)/(๐‘‘๐‘ฅ/๐‘‘๐‘ก) Calculating ๐’…๐’š/๐’…๐’• ๐‘ฆ = ใ€–๐‘Ž๐‘กใ€—^4 ๐‘‘๐‘ฆ/๐‘‘๐‘ก " =" ใ€–4๐‘Ž๐‘กใ€—^(4 โˆ’1) "=" ใ€–4๐‘Ž๐‘กใ€—^3 Calculating ๐’…๐’™/๐’…๐’• ๐‘ฅ = 2ใ€–๐‘Ž๐‘กใ€—^2 ๐‘‘๐‘ฅ/๐‘‘๐‘ก " =" 2 ร— 2๐‘Ž๐‘ก "=" 4๐‘Ž๐‘ก Now, ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘๐‘ฆ/๐‘‘๐‘ก)/(๐‘‘๐‘ฅ/๐‘‘๐‘ก) Putting values ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (4๐‘Ž๐‘ก^3)/4๐‘Ž๐‘ก ๐’…๐’š/๐’…๐’™ = t2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo