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Ex 5.6, 1 If x and y are connected parametrically by the equations without eliminating the parameter, Find ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ, x = 2ใ€–๐‘Ž๐‘กใ€—^2, y = ใ€–๐‘Ž๐‘กใ€—^4Here ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘๐‘ฆ/๐‘‘๐‘ก)/(๐‘‘๐‘ฅ/๐‘‘๐‘ก) Calculating ๐’…๐’š/๐’…๐’• ๐‘ฆ = ใ€–๐‘Ž๐‘กใ€—^4 ๐‘‘๐‘ฆ/๐‘‘๐‘ก " =" ใ€–4๐‘Ž๐‘กใ€—^(4 โˆ’1) "=" ใ€–4๐‘Ž๐‘กใ€—^3 Calculating ๐’…๐’™/๐’…๐’• ๐‘ฅ = 2ใ€–๐‘Ž๐‘กใ€—^2 ๐‘‘๐‘ฅ/๐‘‘๐‘ก " =" 2 ร— 2๐‘Ž๐‘ก "=" 4๐‘Ž๐‘ก Now, ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘๐‘ฆ/๐‘‘๐‘ก)/(๐‘‘๐‘ฅ/๐‘‘๐‘ก) Putting values ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (4๐‘Ž๐‘ก^3)/4๐‘Ž๐‘ก ๐’…๐’š/๐’…๐’™ = t2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.