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Ex 5.6, 2 - Find dy/dx, x = a cos, y = b cos - Chapter 5

Ex 5.6, 2 - Chapter 5 Class 12 Continuity and Differentiability - Part 2

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Ex 5.6, 2 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑π‘₯, π‘₯=π‘Ž cosβ‘πœƒ, 𝑦=𝑏 cosβ‘πœƒHere 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/π‘‘πœƒ)/(𝑑π‘₯/π‘‘πœƒ) Calculating π’…π’š/π’…πœ½ 𝑦 = 𝑏 cosβ‘πœƒ 𝑑𝑦/π‘‘πœƒ = 𝑑(𝑏 π‘π‘œπ‘ β‘πœƒ)/π‘‘πœƒ 𝑑𝑦/π‘‘πœƒ = b . (βˆ’sinβ‘πœƒ ) π’…π’š/π’…πœ½ = βˆ’ 𝐛 𝐬𝐒𝐧 𝜽 Calculating 𝒅𝒙/π’…πœ½ π‘₯=π‘Ž cosβ‘πœƒ 𝑑π‘₯/π‘‘πœƒ = 𝑑(π‘Ž cosβ‘πœƒ )/π‘‘πœƒ 𝑑π‘₯/π‘‘πœƒ = π‘Ž . (βˆ’sinβ‘πœƒ ) 𝒅𝒙/π’…πœ½ = βˆ’π’‚ π’”π’Šπ’β‘πœ½

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.