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Ex 5.6, 2 - Find dy/dx, x = a cos, y = b cos - Chapter 5

Ex 5.6, 2 - Chapter 5 Class 12 Continuity and Differentiability - Part 2

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Ex 5.6, 2 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑π‘₯, π‘₯=π‘Ž cosβ‘πœƒ, 𝑦=𝑏 cosβ‘πœƒHere 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/π‘‘πœƒ)/(𝑑π‘₯/π‘‘πœƒ) Calculating π’…π’š/π’…πœ½ 𝑦 = 𝑏 cosβ‘πœƒ 𝑑𝑦/π‘‘πœƒ = 𝑑(𝑏 π‘π‘œπ‘ β‘πœƒ)/π‘‘πœƒ 𝑑𝑦/π‘‘πœƒ = b . (βˆ’sinβ‘πœƒ ) π’…π’š/π’…πœ½ = βˆ’ 𝐛 𝐬𝐒𝐧 𝜽 Calculating 𝒅𝒙/π’…πœ½ π‘₯=π‘Ž cosβ‘πœƒ 𝑑π‘₯/π‘‘πœƒ = 𝑑(π‘Ž cosβ‘πœƒ )/π‘‘πœƒ 𝑑π‘₯/π‘‘πœƒ = π‘Ž . (βˆ’sinβ‘πœƒ ) 𝒅𝒙/π’…πœ½ = βˆ’π’‚ π’”π’Šπ’β‘πœ½

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.