Ex 5.6, 2 - Find dy/dx, x = a cos, y = b cos - Chapter 5

Ex 5.6, 2 - Chapter 5 Class 12 Continuity and Differentiability - Part 2

Take a fresh quiz. Then take another.
Every attempt is a new AI-adaptive Teachoo quiz with 3 questions, selected from your answers, mistakes, and progress.
Remove Ads
Teachoo Β· Class 12 Explore Class 12

Transcript

Ex 5.6, 2 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑π‘₯, π‘₯=π‘Ž cosβ‘πœƒ, 𝑦=𝑏 cosβ‘πœƒHere 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/π‘‘πœƒ)/(𝑑π‘₯/π‘‘πœƒ) Calculating π’…π’š/π’…πœ½ 𝑦 = 𝑏 cosβ‘πœƒ 𝑑𝑦/π‘‘πœƒ = 𝑑(𝑏 π‘π‘œπ‘ β‘πœƒ)/π‘‘πœƒ 𝑑𝑦/π‘‘πœƒ = b . (βˆ’sinβ‘πœƒ ) π’…π’š/π’…πœ½ = βˆ’ 𝐛 𝐬𝐒𝐧 𝜽 Calculating 𝒅𝒙/π’…πœ½ π‘₯=π‘Ž cosβ‘πœƒ 𝑑π‘₯/π‘‘πœƒ = 𝑑(π‘Ž cosβ‘πœƒ )/π‘‘πœƒ 𝑑π‘₯/π‘‘πœƒ = π‘Ž . (βˆ’sinβ‘πœƒ ) 𝒅𝒙/π’…πœ½ = βˆ’π’‚ π’”π’Šπ’β‘πœ½

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.