Ex 5.6, 4 - Find dy/dx, x = 4t, y = 4/t - Chapter 5 Class 12

Ex 5.6, 4 - Chapter 5 Class 12 Continuity and Differentiability - Part 2

  1. Chapter 5 Class 12 Continuity and Differentiability
  2. Serial order wise

Transcript

Ex 5.6, 4 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑π‘₯, π‘₯ = 4𝑑, 𝑦 = 4/𝑑Here 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/𝑑𝑑)/(𝑑π‘₯/𝑑𝑑) Calculating π’…π’š/𝒅𝒕 𝑑𝑦/𝑑𝑑 " " = 𝑑/𝑑𝑑 (4/𝑑) 𝑑𝑦/𝑑𝑑 = 4 𝑑/𝑑𝑑 (1/𝑑) 𝑑𝑦/𝑑𝑑 = βˆ’ πŸ’/𝒕^𝟐 Calculating 𝒅𝒙/𝒅𝒕 𝑑π‘₯/𝑑𝑑 = 𝑑(4𝑑)/𝑑𝑑 𝑑π‘₯/𝑑𝑑 " " = 4 Therefore 𝑑𝑦/𝑑π‘₯ = (𝑑𝑦/𝑑𝑑)/(𝑑π‘₯/𝑑𝑑) 𝑑𝑦/𝑑π‘₯ = ("βˆ’ " 4/𝑑^2 )/4 π’…π’š/𝒅𝒙 = ("βˆ’" 𝟏)/𝒕^𝟐

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.