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Ex 5.3, 1 - Chapter 5 Class 12 Continuity and Differentiability
Last updated at July 18, 2019 by Teachoo
Transcript
Ex 5.3, 1 Find in, 2 + 3 = sin Given 2 +3 = sin Differentiating both sides . . . (2 + 3 ) = ( sin ) (2 ) + (3 ) = ( sin ) 2 ( ) +3 ( ) = ( sin ) 2 + 3 ( ) = cos 3 ( ) = cos 2 ( ) = ( 2)
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