Ex 5.3, 8 - Chapter 5 Class 12 Continuity and Differentiability
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 5.3, 8 Find in, sin2 + cos2 = 1 sin2 + cos2 = 1 Differentiating both sides . . . . sin2 + cos2 = 1 (sin2 ) + ( cos 2 ) = 0 Calculating Derivative of sin2 & cos 2 sepretaly Finding Derivative of (sin2 ) =2 2 1 . ( sin 2 ) =2 sin . ( sin ) =2 sin cos Finding Derivative of (cos2 ) =2 cos 2 1 . ( cos ) =2 cos . ( sin ) . ( ) = 2 cos sin . Now, (sin2 ) + (cos2 ) = 0 2 sin . cos + 2 cos sin . = 0 2 sin . cos 2 sin . cos . = 0 2 sin . cos . = 2 sin cos sin 2 . = sin 2 = sin 2 sin 2 =
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