# Ex 5.1 ,1 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Ex 5.1, 1 Prove that the function ( ) = 5 3 is continuous at = 0, at = 3 and at = 5 Given ( ) = 5 3 (i) At = f is continuous at x = 0 if ( ) = ( ) Since, L.H.S = R.H.S lim x 0 ( ) = (0) Hence, f is continuous at = (ii) At x = 3 f is continuous at x = 3 if lim x 3 = 3 Since, L.H.S = R.H.S lim x 3 ( ) = ( 3) Hence, f is continuous at = 3 (iii) At = f is continuous at x = 5 if lim x 5 = 5 Since, L.H.S = R.H.S lim x 5 = 5 Hence, f is continuous at = Thus the function is continuous at = , at = & at =

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.