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Ex 5.1, 32 - Chapter 5 Class 12 Continuity and Differentiability (Term 1)
Last updated at March 22, 2023 by Teachoo
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Ex 5.1, 32 You are here
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Transcript
Ex 5.1, 32 Show that the function defined by 𝑓 (𝑥)= |cos𝑥 | is a continuous function.𝑓(𝑥) = |cos𝑥 | Let 𝒈(𝒙) = |𝑥| & 𝒉(𝒙) = cos𝑥 Now, 𝒈𝒐𝒉(𝒙) = g(ℎ(𝑥)) = 𝑔(cos𝑥 ) = |cos𝑥 | = 𝒇(𝒙) Hence, 𝑓(𝑥) = 𝑔𝑜ℎ(𝑥) We know that, 𝒉(𝒙) = cos𝑥 is continuous as cos is continuous & 𝒈(𝒙) = |𝑥| is continuous as it is a modulus function Hence, 𝑔(𝑥) & ℎ(𝑥) are both continuous . We know that If two function of 𝑔(𝑥) & ℎ(𝑥) both continuous, then their composition 𝒈𝒐𝒉(𝒙) is also continuous Hence, 𝒇(𝒙) is continuous . .
