# Ex 5.1, 9 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 5.1, 9 Find all points of discontinuity of f, where f is defined by = , <0 & 1 , 0 Given = , <0 & 1 , 0 Case 1 At x = 0 f is continuous at x = 0 if L.H.L = R.H.L = 0 i.e. lim x 0 = lim x 0 + = 0 & 0 = 1 Thus, L.H.L = R.H.L = f(0) f is continuous at =0 Case 2 Let x = c (where c > 0) = 1 f is continuous at x = c if lim x = ( ) Thus lim x = ( ) f is continuous for =( greater than 0). f is at continuous for all real numbers greater than 0. Case 3 Let x = c (where c < 0) = = = 1 f is continuous at x = c if lim x = ( ) Thus , lim x = ( ) f is continuous for = ( c is less than 0 ) f is continuous for all real numbers less than 0. Thus, f is continuous for x R {0} Hence f(x) is continuous at all points f is continuous

Ex 5.1 ,1

Ex 5.1 ,2

Ex 5.1 ,3

Ex 5.1 ,4

Ex 5.1 ,5

Ex 5.1 ,6

Ex 5.1 ,7

Ex 5.1 ,8

Ex 5.1, 9 Important You are here

Ex 5.1, 10

Ex 5.1, 11

Ex 5.1, 12

Ex 5.1, 13 Important

Ex 5.1, 14

Ex 5.1, 15

Ex 5.1, 16 Important

Ex 5.1, 17

Ex 5.1, 18 Important

Ex 5.1, 19

Ex 5.1, 20

Ex 5.1, 21

Ex 5.1, 22

Ex 5.1, 23

Ex 5.1, 24

Ex 5.1, 25

Ex 5.1, 26

Ex 5.1, 27

Ex 5.1, 28 Important

Ex 5.1, 29

Ex 5.1, 30 Important

Ex 5.1, 31

Ex 5.1, 32

Ex 5.1, 33

Ex 5.1, 34 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.