Ex 5.1 ,2 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at Sept. 24, 2018 by Teachoo

Ex 5.1, 2 - Examine continuity of f(x) = 2x2 - 1 at x = 3 - Ex 5.1

Transcript

Ex 5.1, 2 - Chapter 5 Class 12 Continuity and Differentiability - NCERT Examine the continuity of the function f (x) = 2x^2 - 1 at x = 3. Given f(x) = 2x^2 - 1 Given function is continuous at x = 3 if lim x->3 f(x) = f(3) LHS lim x->3 f(x) = lim x->3 (2x^2 - 1) Putting x = 3 = 2 (3)^2 - 1 = 2 (9) - 1 = 18 - 1 = 17 RHS f(3) = 2 (3)^2 - 1 = 2 (9) - 1 = 18 - 1 = 17 Since, L.H.S = R.H.S lim x->3 f(x) = f(3) Hence, f(x) is continuous at x = 3

Ex 5.1

Ex 5.1 ,2 You are here

Ex 5.2 →

Chapter 5 Class 12 Continuity and Differentiability

Serial order wise

Ex 5.1
Ex 5.2
Ex 5.3
Ex 5.4
Ex 5.5
Ex 5.6
Ex 5.7
Ex 5.8
Examples
Miscellaneous

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.