Ex 5.1 ,2 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at April 16, 2024 by

Ex 5.1, 2 - Examine continuity of f(x) = 2x2 - 1 at x = 3

Transcript

Ex 5.1, 2 Examine the continuity of the function f (x) = 2x2 – 1 at x = 3. 𝑓(π‘₯) is continuous at x = 3 if lim┬(xβ†’3) 𝑓(π‘₯) = 𝑓(3) Since, L.H.S = R.H.S Hence, f is continuous at 𝒙 =3 (π₯𝐒𝐦)┬(π±β†’πŸ‘) 𝒇(𝒙) "= " lim┬(xβ†’3) " "(2π‘₯2βˆ’1) Putting π‘₯ = 3 = 2(3)2 βˆ’ 1 = 2 Γ— 9 βˆ’ 1 = 17 𝒇(πŸ‘) = 2(3)2 βˆ’ 1 = 2 Γ— 9 βˆ’ 1 = 18βˆ’1 = 17

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