Ex 5.1 ,2 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at Sept. 24, 2018 by Teachoo

Ex 5.1, 2 - Examine continuity of f(x) = 2x2 - 1 at x = 3 - Ex 5.1

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Ex 5.1, 2 - Chapter 5 Class 12 Continuity and Differentiability - NCERT Examine the continuity of the function f (x) = 2x^2 - 1 at x = 3. Given f(x) = 2x^2 - 1 Given function is continuous at x = 3 if lim x->3 f(x) = f(3) LHS lim x->3 f(x) = lim x->3 (2x^2 - 1) Putting x = 3 = 2 (3)^2 - 1 = 2 (9) - 1 = 18 - 1 = 17 RHS f(3) = 2 (3)^2 - 1 = 2 (9) - 1 = 18 - 1 = 17 Since, L.H.S = R.H.S lim x->3 f(x) = f(3) Hence, f(x) is continuous at x = 3

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Chapter 5 Class 12 Continuity and Differentiability

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