Ex 5.1, 20 - Ex 5.1

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Ex 5.1, 20 Is the function defined by f (x) = ๐‘ฅ^2 โ€“ sin x + 5 continuous at x = ฯ€? f (x) = ๐‘ฅ^2 โ€“ sin x + 5 Let ๐‘(๐‘ฅ)=๐‘ฅ^2 , ๐‘ž(๐‘ฅ)="sin x " & ๐‘Ÿ(๐‘ฅ) = 5 ๐’‘(๐’™) = ๐‘ฅ^2 is continuous as it is a polynomial ๐’’(๐’™)" = sin x" is continuous at all real numbers ๐’“(๐’™) = 5 is continuous as it is a constant function By Algebra of continuous functions, If ๐‘(๐‘ฅ)" ", ๐‘ž(๐‘ฅ) & ๐‘Ÿ(๐‘ฅ) all are continuous at all real numbers then ๐’‡(๐’™)= ๐’‘(๐’™)โˆ’๐’’(๐’™)+๐’“(๐’™) is continuous at "all real numbers" โˆด ๐‘“(๐‘ฅ) = ๐‘ฅ^2 " โ€“ sin x + 5" is continuous at all real numbers. Thus, ๐‘“(๐‘ฅ) is continuous at ๐’™=๐… Ex 5.1, 20 (Method 1) Is the function defined by f (x) = ๐‘ฅ๏ทฎ2๏ทฏ โ€“ sin x + 5 continuous at x = ฯ€? f (x) = ๐‘ฅ๏ทฎ2๏ทฏ โ€“ sin x + 5 We need to check continuity at ๐‘ฅ=๐œ‹ We know that A function f is continuous at ๐‘ฅ=๐œ‹ i.e. lim๏ทฎxโ†’๐œ‹๏ทฏ ๐‘“ ๐‘ฅ๏ทฏ=๐‘“ ๐œ‹๏ทฏ Thus lim๏ทฎxโ†’๐œ‹๏ทฏ ๐‘“ ๐‘ฅ๏ทฏ=๐‘“ ๐‘๏ทฏ โ‡’ f is continuous at ๐’™=๐… Ex 5.1, 20 (Method 2) Is the function defined by f (x) = ๐‘ฅ๏ทฎ2๏ทฏ โ€“ sin x + 5 continuous at x = ฯ€? f (x) = ๐‘ฅ๏ทฎ2๏ทฏ โ€“ sin x + 5 Let ๐‘ ๐‘ฅ๏ทฏ= ๐‘ฅ๏ทฎ2๏ทฏ , ๐‘ž ๐‘ฅ๏ทฏ=sin x & ๐‘Ÿ ๐‘ฅ๏ทฏ = 5 ๐‘ ๐‘ฅ๏ทฏ = ๐‘ฅ๏ทฎ2๏ทฏ is continuous as it is a polynomial ๐‘ž ๐‘ฅ๏ทฏ=sin x is continuous at all real numbers ๐‘Ÿ ๐‘ฅ๏ทฏ = 5 is continuous as it is a constant function By Algebra of continuous function, If ๐‘ ๐‘ฅ๏ทฏ , ๐‘ž ๐‘ฅ๏ทฏ & ๐‘Ÿ ๐‘ฅ๏ทฏ all are continuous at all real numbers then ๐‘“ ๐‘ฅ๏ทฏ= ๐‘ ๐‘ฅ๏ทฏโˆ’๐‘ž ๐‘ฅ๏ทฏ+๐‘Ÿ ๐‘ฅ๏ทฏ is continuous at all real numbers โˆด ๐‘“ ๐‘ฅ๏ทฏ = ๐‘ฅ๏ทฎ2๏ทฏ โ€“ sin x + 5 is continuous at all real numbers. โ‡’ f is continuous at ๐’™=๐…

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo