Advertisement
Advertisement
Ex 5.1, 31 - Chapter 5 Class 12 Continuity and Differentiability (Term 1)
Last updated at Aug. 13, 2021 by Teachoo
Transcript
Ex 5.1, 31 Show that the function defined by ๐(๐ฅ)=cosโก(๐ฅ^2 ) is a continuous function.๐(๐ฅ) = cosโก(๐ฅ^2 ) Let ๐(๐) = cosโก๐ฅ & ๐(๐) = ๐ฅ^2 Now, ๐๐๐(๐) = g(โ(๐ฅ)) = ๐(๐ฅ^2 ) = cosโก(๐ฅ^2 ) = ๐(๐) Hence, ๐(๐ฅ) = ๐๐โ(๐ฅ) We know that ๐(๐) = cosโก๐ฅ is continuous as cos x is always continuous & ๐(๐) = ๐ฅ^2 is continuous as it is a polynomial Hence, ๐(๐ฅ) & โ(๐ฅ) are both continuous . We know that If two function of ๐(๐ฅ) & โ(๐ฅ) both continuous, then their composition ๐๐๐(๐) is also continuous Hence, ๐(๐) is continuous .
Advertisement
Ex 5.1
Ex 5.1 ,1
Ex 5.1 ,2
Ex 5.1, 3 (a)
Ex 5.1, 3 (b)
Ex 5.1, 3 (c) Important
Ex 5.1, 3 (d) Important
Ex 5.1 ,4
Ex 5.1 ,5 Important
Ex 5.1 ,6
Ex 5.1 ,7 Important
Ex 5.1 ,8
Ex 5.1, 9 Important
Ex 5.1, 10
Ex 5.1, 11
Ex 5.1, 12 Important
Ex 5.1, 13
Ex 5.1, 14
Ex 5.1, 15 Important
Ex 5.1, 16
Ex 5.1, 17 Important
Ex 5.1, 18 Important
Ex 5.1, 19 Important
Ex 5.1, 20
Ex 5.1, 21
Ex 5.1, 22 (i) Important
Ex 5.1, 22 (ii)
Ex 5.1, 22 (iii)
Ex 5.1, 22 (iv) Important
Ex 5.1, 23
Ex 5.1, 24 Important
Ex 5.1, 25
Ex 5.1, 26 Important
Ex 5.1, 27
Ex 5.1, 28 Important
Ex 5.1, 29
Ex 5.1, 30 Important
Ex 5.1, 31 You are here
Ex 5.1, 32
Ex 5.1, 33
Ex 5.1, 34 Important
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.