Misc 8 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at Dec. 8, 2016 by Teachoo

Misc 8 - Differentiate cos (a cos x + b sin x) - CBSE - Finding derivative of a function by chain rule

Transcript

Misc 8 (Method 1) Differentiate 𝑤.𝑟.𝑡. 𝑥 the function, cos ⁡(𝑎 cos⁡𝑥+𝑏 sin⁡𝑥), for some constant 𝑎 and 𝑏. Let 𝑦 = cos ⁡(𝑎 cos⁡𝑥+𝑏 sin⁡𝑥) Differentiating 𝑤.𝑟.𝑡.𝑥. 𝑑𝑦﷮𝑑𝑥﷯ = 𝑑(cos a cos﷮x﷯+b sin﷮x﷯﷯﷯﷮𝑑𝑥﷯ 𝑑𝑦﷮𝑑𝑥﷯ = − sin﷮𝑥﷯ 𝑎 cos⁡𝑥+𝑏 sin⁡𝑥﷯ . 𝑑⁡(𝑎 cos⁡𝑥+𝑏 sin⁡𝑥)﷮𝑑𝑥﷯ = − sin﷮𝑥﷯ 𝑎 cos⁡𝑥+𝑏 sin⁡𝑥﷯ . 𝑎 . 𝑑﷮ cos﷮𝑥﷯﷯﷯﷮𝑑𝑥﷯+𝑏 . 𝑑﷮ sin﷮𝑥﷯﷯﷯﷮𝑑𝑥﷯﷯ = − sin﷮𝑥﷯ 𝑎 cos⁡𝑥+𝑏 sin⁡𝑥﷯ . 𝑎 − sin﷮𝑥﷯﷯+𝑏 cos﷮𝑥﷯﷯﷯ = − sin﷮𝑥﷯ 𝑎 cos⁡𝑥+𝑏 sin⁡𝑥﷯ . − 𝑎 sin﷮𝑥﷯+𝑏 cos﷮𝑥﷯﷯ = − 𝐬𝐢𝐧﷮ 𝒂 𝒄𝒐𝒔⁡𝒙+𝒃 𝒔𝒊𝒏⁡𝒙﷯ 𝒂 𝒔𝒊𝒏﷮𝒙﷯−𝒃 𝒄𝒐𝒔﷮𝒙﷯﷯﷯

Miscellaneous

Misc 8 You are here

Concept wise →

Chapter 5 Class 12 Continuity and Differentiability

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.