Example 35 - Chapter 5 Class 12 Continuity and Differentiability (Term 1)
Last updated at April 13, 2021 by Teachoo
Transcript
Example 35 Find ๐๐ฆ/๐๐ฅ , if ๐ฅ = ๐๐ก2, ๐ฆ = 2๐๐ก . ๐๐ฆ/๐๐ฅ = ๐๐ฆ/๐๐ฅ ร ๐๐ก/๐๐ก ๐๐ฆ/๐๐ฅ = ๐๐ฆ/๐๐ก ร ๐๐ก/๐๐ฅ ๐๐ฆ/๐๐ฅ = (๐๐ฆ/๐๐ก)/(๐๐ฅ/๐๐ก) Calculating ๐ ๐/๐ ๐ ๐ฆ = 2๐๐ก" " ๐๐ฆ/๐๐ก " " = ๐(2๐๐ก)/๐๐ก ๐๐ฆ/๐๐ก = 2๐ . ๐(๐ก)/๐๐ก ๐๐ฆ/๐๐ก = ๐๐ Calculating ๐ ๐/๐ ๐ ๐ฅ=๐๐ก2 ๐๐ฅ/๐๐ก " " = ๐(๐๐ก2)/๐๐ก ๐๐ฅ/๐๐ก " " = ๐ . ๐(๐ก2)/๐๐ก " " ๐๐ฅ/๐๐ก " " = ๐๐๐ Therefore ๐๐ฆ/๐๐ฅ = (๐๐ฆ/๐๐ก)/(๐๐ฅ/๐๐ก) ๐๐ฆ/๐๐ฅ = 2๐/2a๐ก ๐ ๐/๐ ๐ = ๐/๐
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Example 35 You are here
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Chapter 5 Class 12 Continuity and Differentiability (Term 1)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.