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Example 5 - Chapter 5 Class 12 Continuity and Differentiability (Term 1)
Last updated at March 12, 2021 by Teachoo
Transcript
Example 5 Check the points where the constant function π (π₯) = π is continuous. Given π(π₯)=π (where π is any constant) To check continuity of π(π₯), We check itβs if it is continuous at any point x = c Let c be any real number f is continuous at π₯ =π if (π₯π’π¦)β¬(π±βπ) π(π)=π(π) (π₯π’π¦)β¬(π±βπ) π(π) "= " limβ¬(xβπ) " " π = π π(π) = π Since, L.H.S = R.H.S β΄ Function is continuous at x = c Thus, we can write that f is continuous for x = c , where c βπ β΄ f is continuous for every real number.
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Chapter 5 Class 12 Continuity and Differentiability (Term 1)
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.