Last updated at Aug. 19, 2021 by

Transcript

Example 44 Differentiate w.r.t. x, the following function: (iii) log7 (log x) y = log7 (log x) But we do not solve base 7. So, changing base y = log7 ( log x) y = π₯π¨π β‘γ(π₯π¨π β‘γπ)γ γ/π₯π¨π β‘π Now, differentiating ππ¦/ππ₯= π(((logβ‘γ(logβ‘γ7)γ γ)/(log 7))/ππ₯ ππ¦/ππ₯= π/π₯π¨π β‘π (π(logβ‘γ(logβ‘π₯ γ )) )/ππ₯ ππ¦/ππ₯= 1/logβ‘7 . 1/logβ‘π₯ (π(logβ‘π₯))/ππ₯ ππ¦/ππ₯= 1/logβ‘7 . 1/logβ‘π₯ . 1/π₯ π π/π π= π/γπ± πππγβ‘γπ π₯π¨π β‘π γ (As log 7 is constant) ("As (log x)β² =" 1/π₯) ("As (log x)β² =" 1/π₯)

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Example 43 Deleted for CBSE Board 2022 Exams

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.