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Example 23 - Chapter 5 Class 12 Continuity and Differentiability (Term 1)
Last updated at March 22, 2023 by Teachoo
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Transcript
Example 23 Differentiate sin β‘(cos β‘(π₯2)) with respect to π₯ .Let π¦ = " " sin β‘(cos β‘π₯2) We need to find derivative of π¦ π€.π.π‘.π₯ i.e. π¦^β² = (π ππβ‘γ (cosβ‘γπ₯^2 γ )γ ) ππ¦/ππ₯ = π(π ππβ‘γ (cosβ‘γπ₯^2 γ )γ )/ππ₯ = cos (cosβ‘γπ₯^2 γ ) . π(cosβ‘γπ₯^2 γ )/ππ₯ = cos (cosβ‘γπ₯^2 γ ). (βsinβ‘γπ₯^2 γ ) . π(π₯^2 )/ππ₯ = cos (cosβ‘γπ₯^2 γ ). (βsinβ‘γπ₯^2 γ ) . 2π₯ = β 2x sin π^π. cos (cos π^π)
