1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise
  3. Ex 6.3
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Ex 6.3,6 - Chapter 6 Class 12 Application of Derivatives

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Ex 6.3, 6 Find the maximum profit that a company can make, if the profit function is given by š‘(š‘„) = 41 ā€“ 72š‘„ ā€“ 18š‘„2The profit function is given by p(x) = 41 āˆ’ 72x āˆ’ 18x2 pā€™(x) = āˆ’72 āˆ’ 36 x Putting pā€˜ (x) = 0 āˆ’72 āˆ’ 36x = 0 āˆ’36x = 72 š‘„ =(āˆ’72)/36= āˆ’2 Now, Pā€(x) = āˆ’36 Since Pā€ (x) < 0 š‘„=āˆ’2 is the maxima āˆ“ Maximum profit = p(āˆ’2) p(x) = 41 āˆ’ 72x āˆ’ 18x2 š‘(āˆ’2)=41āˆ’72 (āˆ’2)āˆ’18 (āˆ’2)^2 =41+144āˆ’18 (4) =41+144āˆ’72 =113 Hence, the maximum profit is 113 unit.
  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

    3. Ex 6.3

    Examples →
Examples →
Chapter 6 Class 12 Application of Derivatives
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo