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Ex 7.10, 17 By using the properties of definite integrals, evaluate the integrals : โˆซ_0^๐‘Žโ–’โˆš๐‘ฅ/(โˆš๐‘ฅ + โˆš(๐‘Ž โˆ’ ๐‘ฅ)) ๐‘‘๐‘ฅ Let I=โˆซ_0^๐‘Žโ–’โˆš๐‘ฅ/(โˆš๐‘ฅ + โˆš(๐‘Ž โˆ’ ๐‘ฅ)) ๐‘‘๐‘ฅ โˆด I=โˆซ_0^๐‘Žโ–’ใ€–โˆš(๐‘Ž โˆ’ ๐‘ฅ)/(โˆš(๐‘Ž โˆ’ ๐‘ฅ) +โˆš(๐‘Ž โˆ’ (๐‘Ž โˆ’ ๐‘ฅ) )) ๐‘‘๐‘ฅใ€— I= โˆซ_0^๐‘Žโ–’ใ€–โˆš(๐‘Ž โˆ’ ๐‘ฅ)/(โˆš(๐‘Ž โˆ’ ๐‘ฅ) + โˆš(๐‘Ž โˆ’ ๐‘Ž + ๐‘ฅ)) ๐‘‘๐‘ฅใ€— I=โˆซ_0^๐‘Žโ–’ใ€–โˆš(๐‘Ž โˆ’ ๐‘ฅ)/(โˆš(๐‘Ž โˆ’ ๐‘ฅ) + โˆš๐‘ฅ) ๐‘‘๐‘ฅใ€— Adding (1) and (2) i.e (1) + (2) I + I = โˆซ_0^๐‘Žโ–’ใ€–โˆš๐‘ฅ/(โˆš๐‘ฅ +โˆš(๐‘Ž โˆ’ ๐‘ฅ)) ๐‘‘๐‘ฅใ€—+โˆซ_0^๐‘Žโ–’ใ€–โˆš(๐‘Ž โˆ’ ๐‘ฅ)/(โˆš(๐‘Žโˆ’ ๐‘ฅ) + โˆš( ๐‘ฅ)) ๐‘‘๐‘ฅใ€— 2I = โˆซ_0^๐‘Žโ–’ใ€–(โˆš๐‘ฅ + โˆš(๐‘Ž โˆ’ ๐‘ฅ))/(โˆš๐‘ฅ + โˆš(๐‘Ž โˆ’ ๐‘ฅ)) ๐‘‘๐‘ฅใ€— 2I =โˆซ_0^๐‘Žโ–’ใ€–1.๐‘‘๐‘ฅใ€— 2I = [๐‘ฅ]_0^๐‘Ž 2I = [๐‘Žโˆ’0] ๐ˆ =๐’‚/๐Ÿ

  1. Chapter 7 Class 12 Integrals
  2. Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo