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Ex 7.10, 9 By using the properties of definite integrals, evaluate the integrals : โˆซ_0^2โ–’๐‘ฅโกโˆš(2โˆ’๐‘ฅ) ๐‘‘๐‘ฅ Let I=โˆซ_0^2โ–’ใ€–๐‘ฅโˆš(2โˆ’๐‘ฅ) ๐‘‘๐‘ฅใ€— โˆด I=โˆซ_0^2โ–’ใ€–(2โˆ’๐‘ฅ) โˆš(2โˆ’(2โˆ’๐‘ฅ) ) ๐‘‘๐‘ฅใ€— I=โˆซ_0^2โ–’ใ€–(2โˆ’๐‘ฅ) โˆš(2โˆ’2+๐‘ฅ ) ๐‘‘๐‘ฅใ€— I=โˆซ_0^2โ–’ใ€–(2โˆ’๐‘ฅ) โˆš(๐‘ฅ ) ๐‘‘๐‘ฅใ€— I=โˆซ_0^2โ–’ใ€–(2โˆ’๐‘ฅ) (๐‘ฅ)^(1/2) ๐‘‘๐‘ฅใ€— I=โˆซ_0^2โ–’ใ€–(2. ๐‘ฅ^(1/2)โˆ’๐‘ฅ.ใ€– ๐‘ฅใ€—^(1/2) ) ๐‘‘๐‘ฅใ€— I=2โˆซ_0^2โ–’ใ€–๐‘ฅ^(1/2) ๐‘‘๐‘ฅใ€— โˆ’โˆซ_0^2โ–’ใ€–๐‘ฅ. ๐‘ฅ^(3/2) ๐‘‘๐‘ฅใ€— I=2[๐‘ฅ^(1/2 + 1)/(1/2 + 1)]_0^2โˆ’ [๐‘ฅ^(3/2 + 1)/(3/2 + 1)]_0^2 I=2[๐‘ฅ^(3/2 )/(3/2)]_0^2โˆ’ [๐‘ฅ^(5/2)/(5/2)]_0^2 I=(2. 2)/3 [๐‘ฅ^(3/2) ]_0^2โˆ’ ใ€–2/5 [๐‘ฅ^(5/2) ]ใ€—_0^2 I=4/3 [(2)^(3/2)โˆ’(0)^(3/2) ] โˆ’ 2/5 [(2)^(5/2)โˆ’(0)^(5/2) ] I=4/3 [(2)^(3/2) ] โˆ’ 2/5 [(2)^(5/2) ] I=4/3 [[(2)^(1/2) ]^3 ] โˆ’ 2/5 [[(2)^(1/2) ]^3 ] I=4/3 [(โˆš2)^3 ] โˆ’ 2/5 [(โˆš2)^5 ] I=4/3 [2โˆš2] โˆ’ 2/5 [4โˆš2] I=(8โˆš2)/3โˆ’(8โˆš2)/5 I=8โˆš2 [1/3โˆ’1/5] I=8โˆš2 [2/15] ๐ˆ=(๐Ÿ๐Ÿ”โˆš๐Ÿ)/๐Ÿ๐Ÿ“

  1. Chapter 7 Class 12 Integrals
  2. Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo