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Ex 7.10, 6 By using the properties of definite integrals, evaluate the integrals: โˆซ_2^8โ–’ใ€– |๐‘ฅโˆ’5| ใ€— ๐‘‘๐‘ฅ |๐‘ฅโˆ’5|= {โ–ˆ(๐‘ฅโˆ’5, ๐‘–๐‘“ ๐‘ฅโˆ’5โ‰ฅ0@โˆ’(๐‘ฅโˆ’5) ๐‘–๐‘“ ๐‘ฅโˆ’5<0)โ”ค = {โ–ˆ((๐‘ฅโˆ’5) ๐‘–๐‘“ ๐‘ฅโ‰ฅ5@โˆ’(๐‘ฅโˆ’5) ๐‘–๐‘“ ๐‘ฅ<5)โ”ค โˆด โˆซ_2^8โ–’ใ€– |๐‘ฅโˆ’5| ใ€— ๐‘‘๐‘ฅ=โˆซ_2^5โ–’ใ€–โˆ’(๐‘ฅโˆ’5) ใ€— ๐‘‘๐‘ฅ+โˆซ_5^8โ–’|๐‘ฅโˆ’5| ๐‘‘๐‘ฅ =โˆ’ [๐‘ฅ^2/2โˆ’5๐‘ฅ]_2^5+[๐‘ฅ^2/2โˆ’5๐‘ฅ]_5^8 =โˆ’[5^2/2โˆ’5ร—5]+[2^2/2โˆ’5ร—2]+[8^2/2โˆ’5ร—8]โˆ’[5^2/2โˆ’5ร—5] =โˆ’ 25/2+25+2โˆ’10+32โˆ’40โˆ’25/2+25 =โˆ’ 25/2โˆ’25+25โˆ’10โˆ’40+32+2 =(โˆ’50)/2+50โˆ’50+34 =(โˆ’50)/2+34 =18/2 = 9

  1. Chapter 7 Class 12 Integrals
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo