Ex 7.5, 4 - Chapter 7 Class 12 Integrals (Term 2)
Last updated at Sept. 21, 2018 by Teachoo
Transcript
Ex 7.5, 4 π₯/(π₯ β 1)(π₯ β 2)(π₯ β 3) . We can write the integrand as π₯/((π₯ β 1) (π₯ β 2) (π₯ β 3) ) = π΄/((π₯ β 1) ) + π΅/((π₯ β 2) ) + πΆ/((π₯ β 3) ) = (π΄(π₯ β 2)(π₯ β 3) + π΅(π₯ β 1)(π₯ β 3) + πΆ(π₯ β1)(π₯ β 2))/((π₯ β 1) (π₯ β 2) (π₯ β 3) ) By cancelling denominator π₯ = π΄(π₯β2)(π₯β3)+π΅(π₯β1)(π₯β3)+πΆ(π₯β1)(π₯β2) Putting π₯=1, in (1) 1 = π΄(1β2)(1β3)+π΅(1β1)(1β3)+πΆ(1β1)(1β2) 1 = π΄(β1)(β2)+π΅Γ0+πΆΓ0 1 = 2π΄
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