Ex 7.5, 3 - Chapter 7 Class 12 Integrals (Term 2)
Last updated at Aug. 20, 2021 by Teachoo
Ex 7.5
Ex 7.5, 1
Ex 7.5, 2
Ex 7.5, 3 Important You are here
Ex 7.5, 4
Ex 7.5, 5
Ex 7.5, 6 Important
Ex 7.5, 7 Important
Ex 7.5, 8
Ex 7.5, 9 Important
Ex 7.5, 10
Ex 7.5, 11 Important
Ex 7.5, 12
Ex 7.5, 13 Important
Ex 7.5, 14 Important
Ex 7.5, 15
Ex 7.5, 16 Important
Ex 7.5, 17
Ex 7.5, 18 Important
Ex 7.5, 19
Ex 7.5, 20 Important
Ex 7.5, 21 Important
Ex 7.5, 22 (MCQ)
Ex 7.5, 23 (MCQ) Important
Chapter 7 Class 12 Integrals
Serial order wise
Transcript
Ex 7.5, 3 3 1 1 2 3 We can write the integrand as 3 1 1 2 3 = 1 + 2 + 3 = 2 3 + 1 3 + 1 2 1 2 3 By cancelling denominator 3 1 = 2 3 + 1 3 + 1 2 Putting =1 in (1) 3 1 = 1 2 1 3 + 1 1 1 3 + 1 1 1 2 2 = 1 2 + 0+ 0 2 = 2 = 1 Similarly putting =2 , in (1) 3 2 1 = 2 2 2 3 + 2 1 2 3 + 2 1 2 2 6 1 = 0+ 1 1 + 0 5 = = 5 Similarly putting x = 3 , in (1) 3 3 1 = 3 2 3 3 + 3 1 3 3 + 3 1 3 2 9 1 = 0+ 0+ 2 1 8 = 2 = 4 Hence we can write it as 3 1 1 2 3 = 1 1 + 5 2 + 4 3 = 1 1 5 1 2 +4 1 3 = + +
