Check sibling questions


Transcript

Example 24 Find ∫1▒√(3−2𝑥−𝑥^2 ) 𝑑𝑥 ∫1▒〖√(3−2𝑥−𝑥^2 ) 𝑑𝑥〗 =∫1▒√(3−(2𝑥+𝑥^2 ) ) 𝑑𝑥 Adding and Subtracting 1^2 =∫1▒√(3−(𝑥^2+2𝑥+1^2−1^2 ) ) 𝑑𝑥 =∫1▒√(3−(𝑥^2+2𝑥+1^2 )+1) 𝑑𝑥 =∫1▒√(3+1−(𝑥^2+2𝑥+1^2 ) ) 𝑑𝑥 =∫1▒√(4−(𝑥^2+2𝑥+1^2 ) ) 𝑑𝑥 =∫1▒√(2^2−(𝑥+1)^2 ) 𝑑𝑥 It is of the form ∫1▒〖√(𝑎^2−𝑥^2 ) 𝑑𝑥=1/2 𝑥√(𝑎^2−𝑥^2 )+𝑎^2/2 𝑠𝑖𝑛^(−1) 𝑥/𝑎+𝐶〗 Replacing a with 2 and 𝑥 with (𝑥+1) =1/2 (𝑥+1) √(2^2−(𝑥+1)^2 )+2^2/2 𝑠𝑖𝑛^(−1) ((𝑥 + 1))/2+𝐶 =1/2 (𝑥+1) √(4−(𝑥^2+1^2+2𝑥))+2𝑠𝑖𝑛^(−1) ((𝑥 + 1))/2+𝐶 =𝟏/𝟐 (𝒙+𝟏) √(𝟑−𝟐𝒙−𝒙^𝟐 )+𝟐 𝒔𝒊𝒏^(−𝟏) ((𝒙 + 𝟏))/𝟐+𝑪

  1. Chapter 7 Class 12 Integrals
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo