Example 23 - Chapter 7 Class 12 Integrals
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 23 Find 𝑥2+2𝑥+5 𝑑𝑥 𝑥2+2𝑥+5 𝑑𝑥 = 𝑥2+2𝑥+1+4 𝑑𝑥 = (𝑥+1)2+4 𝑑𝑥 Let y = x + 1 𝑑𝑦 𝑑𝑥=1 dy = dx Substituting = 𝑦2+4 𝑑𝑦 = 𝑦2+(2)2 𝑑𝑦 = 𝑦2 𝑦2+4+ 42 log𝑦+𝑦2+4+ C = 𝑦2𝑦2+4+2 𝑙𝑜𝑔𝑦+𝑦2+4+ C Putting value of y = x + 1 = 𝑥 + 12 (𝑥+1)2 + 4+2 𝑙𝑜𝑔𝑥+1+(𝑥+1)2 + 4+ C = 𝑥 + 12𝑥2+1+2𝑥+ 4+2 𝑙𝑜𝑔𝑥+1+𝑥2+1+2𝑥+ 4+ C = 𝟏𝟐 (x + 1) 𝒙𝟐 𝟐𝒙+𝟓+𝟐𝐥𝐨𝐠𝒙+𝟏+𝒙𝟐+𝟐𝒙+𝟓+𝐂
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Example 23 You are here
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About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo