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Ex 9.3

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Ex 9.3, 23 (MCQ) You are here

Last updated at May 29, 2023 by Teachoo

Ex 9.3, 23 The general solution of the differential equation ππ¦/ππ₯=π^(π₯+π¦) is (A) π^π₯+π^(βπ¦)=πΆ (B) π^π₯+π^π¦=πΆ (C) π^(βπ₯)+π^π¦=πΆ (D) π^(βπ₯)+π^(βπ¦)=πΆ ππ¦/ππ₯ = π^(π₯ + π¦) ππ¦/ππ₯ = π^(π₯ ) π^( π¦) ππ¦/π^π¦ = π^(π₯ ) ππ₯ Integrating both sides β«1βπ^(βπ¦) ππ¦= β«1βπ^π₯ ππ₯ γβπγ^(βπ¦) = π^π₯+π π^π₯ + π^(βπ¦) = C β΄ Option (A) is correct.