# Ex 9.4, 10 - Chapter 9 Class 12 Differential Equations

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 9.4, 10 For each of the differential equations in Exercises 1 to 10, find the general solution : ^ tan +(1 ^ ) sec^2 =0 ^ tan +(1 ^ ) sec^2 =0 ^ tan = (1 ^ ) sec^2 ^ tan =( ^ 1) sec^2 ^ /( ^ 1) dx = ( 2 )/tan Integrating both sides. 1 ^ /( ^ 1) = 1 ( 2 )/tan Put ^ 1 = u and put tan y = v Diff u w.r.t. x & v w.r.t y Therefore 1 / / = 1 2 /( 2 ) dv 1 / = 1 / log u + c1 = log v Putting back u = ex 1 and V = tan y log |"ex 1" | + c1 = log tan y Putting c1 = log c log |"ex 1" |+ log c = log (tan y) log | ("ex 1" )|= log |tan | ("ex 1" ) = tan y tan y = c ("ex 1" ) is the general solution

Chapter 9 Class 12 Differential Equations

Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.