Ex 9.4, 3 For each of the differential equations in Exercises 1 to 10, find the general solution : 𝑑𝑦/𝑑𝑥+𝑦=1(𝑦≠1) 𝑑𝑦/𝑑𝑥+𝑦=1 𝑑𝑦/𝑑𝑥=1−𝑦 𝑑𝑦 = (1 − y) dx 𝑑𝑦/(1 − 𝑦) = dx 𝑑𝑦/(𝑦 − 1) = −dx Integrating both sides. ∫1▒〖𝑑𝑦/(𝑦 − 1)=〗 ∫1▒〖−𝑑𝑥〗 log (y − 1) = −x + C y − 1 = e(−x + C) y − 1 = e−x × eC y = e−x × eC + 1 Putting eC = A y = Ae−x + 1 is the general solution

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.

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